修复C语言程序的解决方案
C语言程序改错题解#include#includelongfun(longnum){longk=1;//这里缺少语句结束符分号do{k*=num%10;num/=10;//运算符是/=不是\=}while(!num);//这里缺少do……while语句结束符分号return(k);}main(){longn;printf("\nPleaseenteranumber:");/*想换行使用\n否则去掉斜线*/scanf("%d",&n);printf("\n%ld\n",fun(n));system("pau

C语言程序改错题解
#include
#include
long fun (long num)
{long k=1; //这里缺少语句结束符分号
do
{ k*=num%10 ;
num/=10; //运算符是 /= 不是 \=
}while(!num); //这里缺少 do ……while 语句结束符分号
return (k) ;}
main( )
{ long n ;
printf("\n Please enter a number:") ;/*想换行使用\n 否则去掉斜线*/
scanf("%d",&n);
printf("\n%ld\n", fun(n)) ;
system("pause");
}
通过啦
C程序高手进来下有几题改错题帮忙改下好的话在加50分
改错题:
//后面是改错后的答案
1. x=5b+3a-10;
//x=5*b+3*a-10;
2. int *p,a;*p=&a;
//*p=a;
3. int x; y; z;
//int x,y,z;
4. for (i<=n;i=0;i++) n=n+1;
//for (i=0;i<=n;i++) n=n+1;
5. int a=b=c=0;
//int a=0,b=0,c=0;
6. if x>=y x++ else y++;
//if(x>=y)x++; else y++;
7. int a[5]={3,2,56,,8,9};
//int a[5]={3,2,56,8,9};
8. if (0 //if ((x>0)&&(x<10)) y=x+1; 9. int a[10],i;for(i=0;i<=9;i++); scanf("%d",a[i]); //int a[10],i;for(i=0;i<=9;i++) scanf("%d",a[i]); 10. for(s=0;i=1;i<=10;i++); s+=i; //for(s=0;i=1;i<=10;i++) s+=i; 11. #define PI*r*r //#define XXX PI*r*r(这个应该是有一个define的对象的,暂定叫XXX吧) 12. char str="string"; //char *str="string"; 13. void f1(void) { int x=3;… return x} //int f1(void) { int x=3; return x;} 14. int a; *p=a; //int a; int *p=a; 15. char name[20]; scanf("%s",&name); //char name[20]; scanf("%s",name); public class test { static string a = "10"; static int b = 20, c = 0, d; public static void main(string[] args) { try { d = integer.parseint(a); if (b == 20) throw (new yourexception("特殊错误")); d = b / c; } catch (numberformatexception e) { system.out.println("数据格式错误"); } catch (yourexception e) { system.out.println(e.getexceptionmessage()); } catch (arithmeticexception e) { system.out.println("算术运算错误"); } } } class yourexception extends exception { private string exceptionmessage; public yourexception(string s) { exceptionmessage = s; } public string getexceptionmessage() { return exceptionmessage; } } 错误一: throws(yourexception("特殊错误")); 改成 throw (new yourexception("特殊错误")); 错误二: catch(exception e){ system.out.println(e.getexceptionmessage()); } 改成 catch (yourexception e) { system.out.println(e.getexceptionmessage()); }java程序改错题


































